Web1 jun. 2024 · If tan A = 2, then evaluate sec A . sin A + tan^2A – cosec A. asked Jun 1, 2024 in Trigonometric Ratios of Acute Angles by HarshKumar ( 32.7k points) … Web29 mrt. 2024 · Example 12Express the ratios cos A, tan A and sec A in terms of sin A.cos ASince, cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A cos A = ±√(1 −𝑠𝑖𝑛2 𝐴)Here, A is acute ... Example 12 - Chapter 8 Class 10 Introduction to Trignometry (Term 1) Last updated at March 29, 2024 by Teachoo.
If tan A = 2, then evaluate sec A . sin A + tan^2A – cosec A.
Web21 okt. 2024 · Class 10 Maths MCQs Chapter 8 Introduction to Trigonometry. 1. The value of cos 0°. cos 1°. cos 2°. cos 3°… cos 89° cos 90° is. 2. If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to. 3. If x and y are complementary angles, then. 5. If A, B and C are interior angles of a ΔABC then is equal to. Web29 mrt. 2024 · Example 12 Express the ratios cos A, tan A and sec A in terms of sin A. cos A Since, cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A cos A = ±√(1 −𝑠𝑖𝑛2 𝐴) Here, A is acute (i.e. … enumerate local users on domain
If sinA=(3/5) and A is in first quadrant, then the values of sin2A ...
Web1 jun. 2024 · Prove that √(sec^2A + cosec^2A) = tanA + cotA. asked Jun 1, 2024 in Trigonometric Ratios of Acute Angles by HarshKumar ( 32.7k points) trigonometric ratios … Websec ( A) = cosec ( B) Solution The correct option is D sec ( A) = cosec ( B) Given, A and B are complementary angles. ⇒ m ∠ A + m ∠ B = 90 ∘ ⇒ A = 90 - B ... ( i) We know that , sin θ = cos 90 - θ Taking reciprocal on both sides we get, ⇒ 1 sin θ = 1 cos 90 - θ ⇒ cos e c θ = s e c 90 - θ Now, replace θ by B ⇒ cos e c B = s e c 90 - B Websec A - tan A = 5, or (1/cos A) - (sin A/cos A) = 5, or 1-sin A = 5 cos A, or 1-sin A = 5 (1-sin^2 A)^0.5, or Square both sides (1-sin A)^2 = 25 (1-sin^2 A) 1 - 2 sin A + sin^2 A = 25 - 25 sin^2 A, or 26sin^2 A - 2 sin A - 24 = 0, or 13 sin^2 A - sin A - 12 = 0. sin A (1) = [+1+ (1+625)^0.5]/26 = [+1+25]/26 = 26/26 = 1 Hence A (1) = 90 deg enumerate meaning in telugu