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WebAnswer (1 of 2): x^2 = t^2 +1 2x dx/dt = 2t v= dx/dt = t/x a = dv/dt = [x - t .dx/dt]/x^2 a = [(t^2+1)^0.5 - t(t/x)]/x^2 substitute in values for x^2 = t^2 +1 and for x , get a common … WebIf x= 1+t t3,y= 3 2t2+ 2 t, then x(dy dx)3 − dy dx is equal to Q. If x= a 1+t3,y= at 1+t3 then show that dy dx at t=1 is 1 p then p= View More Related Videos Parametric … kamloops airport transfer to sun peaks
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